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-5x^2-5x+60=0
a = -5; b = -5; c = +60;
Δ = b2-4ac
Δ = -52-4·(-5)·60
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*-5}=\frac{-30}{-10} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*-5}=\frac{40}{-10} =-4 $
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